![]() Pay special attention to the number of backslashes when rewriting a regular expression as a string literal.“Invalid escape sequence” is most common error at compile time while using Regular Exception or defining File Path while file handling for reading and writing files.Īs per JAVA only valid sequence characters are (\b, \t, \n, \f, \r, \”, \’, \). Recommendation ¶Įnsure that the right amount of backslashes is used when escaping characters in strings, template literals and regular expressions. The problem occurs when a regular expression escape sequence loses its special meaning in a string literal. This can be problematic when a regular expression literal is turned into a regular expression that is built from one or more string literals. The set of characters that change meaning when in escape sequences is different for regular expression literals and string literals. Such superfluous escape sequences are usually benign, and do not change the behavior of the program. For example, the escape sequence \k in a string literal just means k. In this case, the backslash just makes the character appear to mean something else, and the backslash actually has no effect. However, not all characters change meaning when used in an escape sequence. For example, the escape sequence \n in a string literal corresponds to a single newline character, and not the \ and n characters. When a character in a string literal or regular expression literal is preceded by a backslash, it is interpreted as part of an escape sequence.
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